3.322 \(\int \frac{(f x)^m (a+b \log (c x^n))}{d+e x^2} \, dx\)

Optimal. Leaf size=27 \[ \text{Unintegrable}\left (\frac{(f x)^m \left (a+b \log \left (c x^n\right )\right )}{d+e x^2},x\right ) \]

[Out]

Unintegrable[((f*x)^m*(a + b*Log[c*x^n]))/(d + e*x^2), x]

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Rubi [A]  time = 0.067045, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int \frac{(f x)^m \left (a+b \log \left (c x^n\right )\right )}{d+e x^2} \, dx \]

Verification is Not applicable to the result.

[In]

Int[((f*x)^m*(a + b*Log[c*x^n]))/(d + e*x^2),x]

[Out]

Defer[Int][((f*x)^m*(a + b*Log[c*x^n]))/(d + e*x^2), x]

Rubi steps

\begin{align*} \int \frac{(f x)^m \left (a+b \log \left (c x^n\right )\right )}{d+e x^2} \, dx &=\int \frac{(f x)^m \left (a+b \log \left (c x^n\right )\right )}{d+e x^2} \, dx\\ \end{align*}

Mathematica [A]  time = 0.199069, size = 108, normalized size = 4. \[ \frac{x (f x)^m \left ((m+1) \, _2F_1\left (1,\frac{m+1}{2};\frac{m+3}{2};-\frac{e x^2}{d}\right ) \left (a+b \log \left (c x^n\right )\right )-b n \, _3F_2\left (1,\frac{m}{2}+\frac{1}{2},\frac{m}{2}+\frac{1}{2};\frac{m}{2}+\frac{3}{2},\frac{m}{2}+\frac{3}{2};-\frac{e x^2}{d}\right )\right )}{d (m+1)^2} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[((f*x)^m*(a + b*Log[c*x^n]))/(d + e*x^2),x]

[Out]

(x*(f*x)^m*(-(b*n*HypergeometricPFQ[{1, 1/2 + m/2, 1/2 + m/2}, {3/2 + m/2, 3/2 + m/2}, -((e*x^2)/d)]) + (1 + m
)*Hypergeometric2F1[1, (1 + m)/2, (3 + m)/2, -((e*x^2)/d)]*(a + b*Log[c*x^n])))/(d*(1 + m)^2)

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Maple [A]  time = 0.625, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( fx \right ) ^{m} \left ( a+b\ln \left ( c{x}^{n} \right ) \right ) }{e{x}^{2}+d}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((f*x)^m*(a+b*ln(c*x^n))/(e*x^2+d),x)

[Out]

int((f*x)^m*(a+b*ln(c*x^n))/(e*x^2+d),x)

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Maxima [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \log \left (c x^{n}\right ) + a\right )} \left (f x\right )^{m}}{e x^{2} + d}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)^m*(a+b*log(c*x^n))/(e*x^2+d),x, algorithm="maxima")

[Out]

integrate((b*log(c*x^n) + a)*(f*x)^m/(e*x^2 + d), x)

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Fricas [A]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\left (f x\right )^{m} b \log \left (c x^{n}\right ) + \left (f x\right )^{m} a}{e x^{2} + d}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)^m*(a+b*log(c*x^n))/(e*x^2+d),x, algorithm="fricas")

[Out]

integral(((f*x)^m*b*log(c*x^n) + (f*x)^m*a)/(e*x^2 + d), x)

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Sympy [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (f x\right )^{m} \left (a + b \log{\left (c x^{n} \right )}\right )}{d + e x^{2}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)**m*(a+b*ln(c*x**n))/(e*x**2+d),x)

[Out]

Integral((f*x)**m*(a + b*log(c*x**n))/(d + e*x**2), x)

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Giac [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \log \left (c x^{n}\right ) + a\right )} \left (f x\right )^{m}}{e x^{2} + d}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)^m*(a+b*log(c*x^n))/(e*x^2+d),x, algorithm="giac")

[Out]

integrate((b*log(c*x^n) + a)*(f*x)^m/(e*x^2 + d), x)